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Q of the D

Original post by Toucan311

True or False.

If F(x) is an antiderivative of f(x) and c is any constant, then F(x) + c is also an antiderivative of f(x).
Celest Posted:

Re: Q of the D


Posted by Kerin2804


Posted by Celest

NO the answer is

The function F(x) = x3/3 is an antiderivative of f(x) = x2. As the derivative of a constant is zero, x2 will have an infinite number of antiderivatives; such as (x3/3) + 0, (x3 / 3) + 7, (x3 / 3) - 42, etc. Thus, the entire antiderivative family of x2 can be obtained by changing the value of C in F(x) = (x3 / 3) + C; where C is an arbitrary constant known as the constant of integration. Essentially, the graphs of antiderivatives of a given function are vertical translations of each other; each graph's location depending upon the value of C.





OMG I wish I could comprehend math the way you do !!!



You too can comprehend math as I do. it is called Google & copying random stuf & pasting it. I know it is a highly trained talent I have, honed from years of doing nothing but searching the net.

Hold you applause though I easily get embarrassed.
Celest Posted:

Re: Q of the D


Posted by JBoothIn2008


Posted by Celest


Posted by JBoothIn2008


Posted by Celest

Oohh lets do another

Candace is Jane's daughter's aunt's husband's daughter's sister. What is the relationship between Candance and Jane?



Candace is Jane's niece.

That seemed too easy .... am i right?



Correct. Prizes are pending



If you are taking suggestions for those prizes, I really need a massage. And I do not really care who gives it to me at this point.



well I have a prize for massaging a horse but I do not think that is what you meant. perhaps mima will want


Toucan311 Posted:

Re: Q of the D

Those are some hooves.

Celest Posted:

Re: Q of the D


Posted by Mimacat

Those are some hooves.


FCsBride914 Posted:

Re: Q of the D

I'm Clueless

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